Maths - Pointless

Theorem :
         All numbers are equal
Proof :
       Consider any two numbers a and b . Let t = a + b


a + b = t
(a+b)(a-b)=(a-b)t            [Multiply (a-b) on both sides]
a^2 - b^2 = ta - tb
a^2 - ta  = b^2 - tb
a^2 - ta +(t/2)^2 = b^2 - tb +(t/2)^2
                             [Add (t/2)^2 on both sides]
(a-t/2)^2=(b-t/2)^2
a - t/2 = b - t/2            [Take square root on both sides]
a = b




  So All Numbers Are Equal . Maths Is Pointless .
      This is also from the feild of mathematical fallacy . Try to find the fallacy if you can .